26:I[49711,["/_next/static/chunks/0t1_7x_uuxe34.js","/_next/static/chunks/0~ta-e_o9dqvm.js","/_next/static/chunks/115lbazto1qq7.js","/_next/static/chunks/0vq81gpimz.3f.js","/_next/static/chunks/0jal2z51-yxb_.js"],"default"] 27:T474,The expression $\lim\limits_{x \to 2^+} f(x) = 3$ states that the limit of $f$ as $x$ approaches $2$ from the right side is equal to $3$. **A** [[graph 1]] In graph A, $\lim\limits_{x \to 2^+} f(x)$ seems to equal to $1$. **B** [[graph 2]] In graph B, $\lim\limits_{x \to 2^+} f(x)$ seems to be equal to $3$. **C** [[graph 3]] In graph C, $\lim\limits_{x \to 2^+} f(x)$ seems to be equal to $3$ as well. **In conclusion, these graphs agree with $\lim\limits_{x \to 2^+} f(x) = 3$.** * **Graph B** * **Graph C** --- Licensing information: The question comes from Khan Academy, and is licensed under a creative commons license. The original quiz containing this question can be found here: Quiz 1. Note: All Khan Academy content is available for free at www.khanacademy.org.28:T507,The expression $\lim\limits_{x \to -4} h(x)$ represents the limit of $h$ as $x$ approaches $-4$. Is this limit equal to $-2$? [[graph 1]] Since the function doesn't approach the same value from both sides, $\lim\limits_{x \to -4} h(x)$ doesn't exist (specifically, it isn't equal to $-2$). [[graph 2]] $\lim\limits_{x \to 0^+} h(x)$ represents the limit of $h$ as $x$ approaches $0$ from the right, and that value seems to be $2$. [[graph 3]] $\lim\limits_{x \to 4^-} h(x)$ indeed seems to be equal to $2$. **In conclusion these limit expressions agree with the graph:** * $\lim\limits_{x \to 0^+} h(x) = 2$ * $\lim\limits_{x \to 4^-} h(x) = 2$ --- Licensing information: The question comes from Khan Academy, and is licensed under a creative commons license. The original test containing this question can be found here: Unit Test. Note: All Khan Academy content is available for free at www.khanacademy.org. 29:T542,The expression $\lim\limits_{x \to -4} h(x)$ represents the limit of $h$ as $x$ approaches $-4$. Is this limit equal to $-2$? [[graph 1]] Since the function doesn't approach the same value from both sides, $\lim\limits_{x \to -4}h(x)$ doesn't exist (specifically, it isn't equal to $-2$). [[graph 2]] $\lim\limits_{x \to 0^+} h(x)$ represents the limit of $h$ as $x$ approaches $0$ from the right, and that value seems to be $2$. [[graph 3]] $\lim\limits_{x \to 4^-} h(x)$ indeed seems to be equal to $2$. **In conclusion, these limit expressions agree with the graph:** * $\lim\limits_{x \to 0^+}h(x) =2$ * $\lim\limits_{x \to 4^-}h(x) = 2$ --- Licensing information: The question comes from Khan Academy, and is licensed under a creative commons license. The original exercise containing this question can be found here: Connecting limits and graphical behavior. Note: All Khan Academy content is available for free at www.khanacademy.org. 2a:T4a3,The expression $\lim\limits_{x \to 2^+} f(x)=3$ states that the lim