28:T40f,According to the graph, $\lim\limits_{x \to 3} f(x) = 2$. Now we can find $\lim\limits_{x \to 3} \big(5f(x)\big)$ using the fact that the limit of a multiple of a function is the multiple of the limit: $\lim\limits_{x \to 3} \big(5f(x)\big) = 5 \cdot \lim\limits_{x \to 3} f(x)$ **Putting it all together:** $\lim\limits_{x \to 3} \big(5f(x)\big)$ $= 5 \cdot \lim\limits_{x \to 3} f(x)$ $= 5 \cdot 2$ $=10$ --- Licensing information: The question comes from Khan Academy, and is licensed under a creative commons license. The original test containing this question can be found here: Unit Test. Note: All Khan Academy content is available for free at www.khanacademy.org. 29:T436,According to the graph, $\lim\limits_{x \to -3} h(x) =4$. Now we can find $\lim\limits_{x \to -3} \big(0.5h(x)\big)$ using the fact that the limit of a multiple of a function is the multiple of the limit: $\lim\limits_{x \to -3} \big(0.5h(x)\big) = 0.5 \cdot \lim\limits_{x \to -3} h(x)$ **Putting it all together:** $\lim\limits_{x \to -3} \big(0.5h(x)\big)$ $= 0.5 \cdot \lim\limits_{x \to -3}h(x)$ $=0.5 \cdot 4$ $=2$ --- Licensing information: The question comes from Khan Academy, and is licensed under a creative commons license. The original exercise containing this question can be found here: Limits of combined functions: sums and differences. Note: All Khan Academy content is available for free at www.khanacademy.org.